Search a number
-
+
1400011113 = 33737391693
BaseRepresentation
bin101001101110010…
…0111100101101001
310121120100221012110
41103130213211221
510331400323423
6350531032533
746456620024
oct12334474551
93546327173
101400011113
116592a7086
12330a3b749
13194083857
14d3d161bb
1582d98193
hex53727969

1400011113 has 16 divisors (see below), whose sum is σ = 1875325760. Its totient is φ = 929029824.

The previous prime is 1400011111. The next prime is 1400011121. The reversal of 1400011113 is 3111100041.

It is not a de Polignac number, because 1400011113 - 21 = 1400011111 is a prime.

It is a super-2 number, since 2×14000111132 = 3920062233046997538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1400011111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 826095 + ... + 827787.

It is an arithmetic number, because the mean of its divisors is an integer number (117207860).

Almost surely, 21400011113 is an apocalyptic number.

It is an amenable number.

1400011113 is a deficient number, since it is larger than the sum of its proper divisors (475314647).

1400011113 is a wasteful number, since it uses less digits than its factorization.

1400011113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2808.

The product of its (nonzero) digits is 12, while the sum is 12.

The square root of 1400011113 is about 37416.7223711538. The cubic root of 1400011113 is about 1118.6919020712.

Adding to 1400011113 its reverse (3111100041), we get a palindrome (4511111154).

The spelling of 1400011113 in words is "one billion, four hundred million, eleven thousand, one hundred thirteen".

Divisors: 1 3 373 739 1119 1693 2217 5079 275647 631489 826941 1251127 1894467 3753381 466670371 1400011113