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140004433 is a prime number
BaseRepresentation
bin10000101100001…
…00110001010001
3100202102221222101
420112010301101
5241320120213
621520440401
73320006122
oct1026046121
9322387871
10140004433
1172035448
123aa79101
132300c37a
1414846049
15c457bdd
hex8584c51

140004433 has 2 divisors, whose sum is σ = 140004434. Its totient is φ = 140004432.

The previous prime is 140004413. The next prime is 140004439. The reversal of 140004433 is 334400041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138133009 + 1871424 = 11753^2 + 1368^2 .

It is an emirp because it is prime and its reverse (334400041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140004433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140004433.

It is not a weakly prime, because it can be changed into another prime (140004439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70002216 + 70002217.

It is an arithmetic number, because the mean of its divisors is an integer number (70002217).

Almost surely, 2140004433 is an apocalyptic number.

It is an amenable number.

140004433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140004433 is an equidigital number, since it uses as much as digits as its factorization.

140004433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 19.

The square root of 140004433 is about 11832.3468931569. The cubic root of 140004433 is about 519.2548906812.

Adding to 140004433 its reverse (334400041), we get a palindrome (474404474).

The spelling of 140004433 in words is "one hundred forty million, four thousand, four hundred thirty-three".