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14001058035 = 335103711541
BaseRepresentation
bin11010000101000011…
…10011000011110011
31100010202110102221000
431002201303003303
5212133232324120
610233151133043
71003650013116
oct150241630363
940122412830
1014001058035
115a35261148
122868b14183
1314218bc633
1496b6b057d
1556e291990
hex3428730f3

14001058035 has 16 divisors (see below), whose sum is σ = 24890770080. Its totient is φ = 7467230880.

The previous prime is 14001058013. The next prime is 14001058073. The reversal of 14001058035 is 53085010041.

14001058035 is a `hidden beast` number, since 1 + 40 + 0 + 10 + 580 + 35 = 666.

It is not a de Polignac number, because 14001058035 - 25 = 14001058003 is a prime.

It is a super-2 number, since 2×140010580352 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51855636 + ... + 51855905.

It is an arithmetic number, because the mean of its divisors is an integer number (1555673130).

Almost surely, 214001058035 is an apocalyptic number.

14001058035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

14001058035 is a deficient number, since it is larger than the sum of its proper divisors (10889712045).

14001058035 is a wasteful number, since it uses less digits than its factorization.

14001058035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103711555 (or 103711549 counting only the distinct ones).

The product of its (nonzero) digits is 2400, while the sum is 27.

Adding to 14001058035 its reverse (53085010041), we get a palindrome (67086068076).

The spelling of 14001058035 in words is "fourteen billion, one million, fifty-eight thousand, thirty-five".

Divisors: 1 3 5 9 15 27 45 135 103711541 311134623 518557705 933403869 1555673115 2800211607 4667019345 14001058035