Base | Representation |
---|---|
bin | 1100101110111110010011… |
… | …1111010100110101001011 |
3 | 1211120111101112110022002101 |
4 | 3023233210333110311023 |
5 | 3313343313344121212 |
6 | 45440011322014231 |
7 | 2643356210161546 |
oct | 313574477246513 |
9 | 54514345408071 |
10 | 14001140223307 |
11 | 45089397132a6 |
12 | 16a1621647377 |
13 | 7a73c0248cb3 |
14 | 365931a7b85d |
15 | 19430607c157 |
hex | cbbe4fd4d4b |
14001140223307 has 2 divisors, whose sum is σ = 14001140223308. Its totient is φ = 14001140223306.
The previous prime is 14001140223211. The next prime is 14001140223311. The reversal of 14001140223307 is 70332204110041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14001140223307 - 223 = 14001131834699 is a prime.
It is not a weakly prime, because it can be changed into another prime (14001140220307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000570111653 + 7000570111654.
It is an arithmetic number, because the mean of its divisors is an integer number (7000570111654).
Almost surely, 214001140223307 is an apocalyptic number.
14001140223307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14001140223307 is an equidigital number, since it uses as much as digits as its factorization.
14001140223307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 14001140223307 its reverse (70332204110041), we get a palindrome (84333344333348).
The spelling of 14001140223307 in words is "fourteen trillion, one billion, one hundred forty million, two hundred twenty-three thousand, three hundred seven".
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