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14001153 = 34667051
BaseRepresentation
bin110101011010…
…010000000001
3222100022222020
4311122100001
512041014103
61220032053
7230002455
oct65322001
928308866
1014001153
1179a3301
124832629
132b92b0a
141c06665
151368753
hexd5a401

14001153 has 4 divisors (see below), whose sum is σ = 18668208. Its totient is φ = 9334100.

The previous prime is 14001151. The next prime is 14001179. The reversal of 14001153 is 35110041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35110041 = 311703347.

It is a cyclic number.

It is not a de Polignac number, because 14001153 - 21 = 14001151 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14001151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2333523 + ... + 2333528.

It is an arithmetic number, because the mean of its divisors is an integer number (4667052).

Almost surely, 214001153 is an apocalyptic number.

It is an amenable number.

14001153 is a deficient number, since it is larger than the sum of its proper divisors (4667055).

14001153 is an equidigital number, since it uses as much as digits as its factorization.

14001153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4667054.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 14001153 is about 3741.8114597077. The cubic root of 14001153 is about 241.0208426503.

Adding to 14001153 its reverse (35110041), we get a palindrome (49111194).

The spelling of 14001153 in words is "fourteen million, one thousand, one hundred fifty-three".

Divisors: 1 3 4667051 14001153