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140012000013433 is a prime number
BaseRepresentation
bin11111110101011100010101…
…100001100110110001111001
3200100202000110000101101101011
4133311130111201212301321
5121322424034000412213
61213440342544553521
741330350611520012
oct3765342541466171
9610660400341334
10140012000013433
11406808349a1a19
121385331b6228a1
1360180c887b372
14268088cd10009
15112c077c6103d
hex7f5715866c79

140012000013433 has 2 divisors, whose sum is σ = 140012000013434. Its totient is φ = 140012000013432.

The previous prime is 140012000013409. The next prime is 140012000013439. The reversal of 140012000013433 is 334310000210041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86680717821504 + 53331282191929 = 9310248^2 + 7302827^2 .

It is an emirp because it is prime and its reverse (334310000210041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140012000013433 - 229 = 140011463142521 is a prime.

It is not a weakly prime, because it can be changed into another prime (140012000013439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006000006716 + 70006000006717.

It is an arithmetic number, because the mean of its divisors is an integer number (70006000006717).

Almost surely, 2140012000013433 is an apocalyptic number.

It is an amenable number.

140012000013433 is a deficient number, since it is larger than the sum of its proper divisors (1).

140012000013433 is an equidigital number, since it uses as much as digits as its factorization.

140012000013433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 140012000013433 its reverse (334310000210041), we get a palindrome (474322000223474).

The spelling of 140012000013433 in words is "one hundred forty trillion, twelve billion, thirteen thousand, four hundred thirty-three".