140012040314041 has 4 divisors (see below), whose sum is σ = 160013760358912. Its totient is φ = 120010320269172.

The previous prime is 140012040313993. The next prime is 140012040314057. The reversal of 140012040314041 is 140413040210041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140012040314041 - 2⁷ = 140012040313913 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140012040313997 and 140012040314015.

It is not an unprimeable number, because it can be changed into a prime (140012040314141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10000860022425 + ... + 10000860022438.

It is an arithmetic number, because the mean of its divisors is an integer number (40003440089728).

Almost surely, 2^{140012040314041} is an apocalyptic number.

It is an amenable number.

140012040314041 is a deficient number, since it is larger than the sum of its proper divisors (20001720044871).

140012040314041 is an equidigital number, since it uses as much as digits as its factorization.

140012040314041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20001720044870.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 140012040314041 its reverse (140413040210041), we get a palindrome (280425080524082).

The spelling of 140012040314041 in words is "one hundred forty trillion, twelve billion, forty million, three hundred fourteen thousand, forty-one".