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1400121432331 is a prime number
BaseRepresentation
bin10100010111111101101…
…111011001100100001011
311221211221212111012022121
4110113331233121210023
5140414422041313311
62551112405232111
7203104212545116
oct24277557314413
94854855435277
101400121432331
1149a874058196
121a7429a02637
13a2052b12a1b
144baa27b957d
1526648b49b71
hex145fdbd990b

1400121432331 has 2 divisors, whose sum is σ = 1400121432332. Its totient is φ = 1400121432330.

The previous prime is 1400121432313. The next prime is 1400121432361. The reversal of 1400121432331 is 1332341210041.

Together with previous prime (1400121432313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1400121432331 - 25 = 1400121432299 is a prime.

It is a super-2 number, since 2×14001214323312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1400121432296 and 1400121432305.

It is not a weakly prime, because it can be changed into another prime (1400121432361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700060716165 + 700060716166.

It is an arithmetic number, because the mean of its divisors is an integer number (700060716166).

Almost surely, 21400121432331 is an apocalyptic number.

1400121432331 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400121432331 is an equidigital number, since it uses as much as digits as its factorization.

1400121432331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1400121432331 its reverse (1332341210041), we get a palindrome (2732462642372).

The spelling of 1400121432331 in words is "one trillion, four hundred billion, one hundred twenty-one million, four hundred thirty-two thousand, three hundred thirty-one".