Base | Representation |
---|---|
bin | 11111110101011100100011… |
… | …111000111111010011010011 |
3 | 200100202001001210220000000021 |
4 | 133311130203320333103103 |
5 | 121322430032200233321 |
6 | 1213440422514404311 |
7 | 41330356566212233 |
oct | 3765344370772323 |
9 | 610661053800007 |
10 | 140012241024211 |
11 | 40680948a45986 |
12 | 13853388290697 |
13 | 60181367942aa |
14 | 26808b2d29cc3 |
15 | 112c08debb941 |
hex | 7f5723e3f4d3 |
140012241024211 has 4 divisors (see below), whose sum is σ = 140084748660024. Its totient is φ = 139939733388400.
The previous prime is 140012241024143. The next prime is 140012241024247. The reversal of 140012241024211 is 112420142210041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140012241024211 - 211 = 140012241022163 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140012241022211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36253815010 + ... + 36253818871.
It is an arithmetic number, because the mean of its divisors is an integer number (35021187165006).
Almost surely, 2140012241024211 is an apocalyptic number.
140012241024211 is a deficient number, since it is larger than the sum of its proper divisors (72507635813).
140012241024211 is an equidigital number, since it uses as much as digits as its factorization.
140012241024211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72507635812.
The product of its (nonzero) digits is 1024, while the sum is 25.
Adding to 140012241024211 its reverse (112420142210041), we get a palindrome (252432383234252).
The spelling of 140012241024211 in words is "one hundred forty trillion, twelve billion, two hundred forty-one million, twenty-four thousand, two hundred eleven".
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