Base | Representation |
---|---|
bin | 11111110101011100101101… |
… | …101100000111000110100011 |
3 | 200100202001111021020012020220 |
4 | 133311130231230013012203 |
5 | 121322430401241423301 |
6 | 1213440451110134123 |
7 | 41330363633441454 |
oct | 3765345554070643 |
9 | 610661437205226 |
10 | 140012405420451 |
11 | 40680a22820243 |
12 | 13853413351343 |
13 | 6018161863a85 |
14 | 26808caac112b |
15 | 112c09d641936 |
hex | 7f572db071a3 |
140012405420451 has 4 divisors (see below), whose sum is σ = 186683207227272. Its totient is φ = 93341603613632.
The previous prime is 140012405420401. The next prime is 140012405420473. The reversal of 140012405420451 is 154024504210041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140012405420451 - 219 = 140012404896163 is a prime.
It is not an unprimeable number, because it can be changed into a prime (140012405420401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23335400903406 + ... + 23335400903411.
It is an arithmetic number, because the mean of its divisors is an integer number (46670801806818).
Almost surely, 2140012405420451 is an apocalyptic number.
140012405420451 is a deficient number, since it is larger than the sum of its proper divisors (46670801806821).
140012405420451 is an equidigital number, since it uses as much as digits as its factorization.
140012405420451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46670801806820.
The product of its (nonzero) digits is 25600, while the sum is 33.
Adding to 140012405420451 its reverse (154024504210041), we get a palindrome (294036909630492).
The spelling of 140012405420451 in words is "one hundred forty trillion, twelve billion, four hundred five million, four hundred twenty thousand, four hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •