1400131244401 has 4 divisors (see below), whose sum is σ = 1407167080000. Its totient is φ = 1393095408804.

The previous prime is 1400131244399. The next prime is 1400131244417. The reversal of 1400131244401 is 1044421310041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1400131244401 - 2¹ = 1400131244399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1400131244441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3517917501 + ... + 3517917898.

It is an arithmetic number, because the mean of its divisors is an integer number (351791770000).

Almost surely, 2^{1400131244401} is an apocalyptic number.

It is an amenable number.

1400131244401 is a deficient number, since it is larger than the sum of its proper divisors (7035835599).

1400131244401 is an equidigital number, since it uses as much as digits as its factorization.

1400131244401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7035835598.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1400131244401 its reverse (1044421310041), we get a palindrome (2444552554442).

The spelling of 1400131244401 in words is "one trillion, four hundred billion, one hundred thirty-one million, two hundred forty-four thousand, four hundred one".