140013233120113 has 4 divisors (see below), whose sum is σ = 140144209017460. Its totient is φ = 139882257222768.

The previous prime is 140013233120093. The next prime is 140013233120161. The reversal of 140013233120113 is 311021332310041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 109231908279649 + 30781324840464 = 10451407^2 + 5548092^2 .

It is a cyclic number.

It is not a de Polignac number, because 140013233120113 - 2⁴¹ = 137814209864561 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140013233129113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65487947070 + ... + 65487949207.

It is an arithmetic number, because the mean of its divisors is an integer number (35036052254365).

Almost surely, 2^{140013233120113} is an apocalyptic number.

It is an amenable number.

140013233120113 is a deficient number, since it is larger than the sum of its proper divisors (130975897347).

140013233120113 is a wasteful number, since it uses less digits than its factorization.

140013233120113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 130975897346.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 140013233120113 its reverse (311021332310041), we get a palindrome (451034565430154).

The spelling of 140013233120113 in words is "one hundred forty trillion, thirteen billion, two hundred thirty-three million, one hundred twenty thousand, one hundred thirteen".