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1400133000403 = 13611028753123
BaseRepresentation
bin10100010111111110011…
…011100001110011010011
311221211222200020220201201
4110113332123201303103
5140414433022003103
62551113501212031
7203104413065224
oct24277633416323
94854880226651
101400133000403
1149a87a639485
121a7431861017
13a2055333237
144baa414b24b
1526649b8251d
hex145fe6e1cd3

1400133000403 has 4 divisors (see below), whose sum is σ = 1401161754888. Its totient is φ = 1399104245920.

The previous prime is 1400133000397. The next prime is 1400133000419. The reversal of 1400133000403 is 3040003310041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1400133000403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1400133000463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 514375201 + ... + 514377922.

It is an arithmetic number, because the mean of its divisors is an integer number (350290438722).

Almost surely, 21400133000403 is an apocalyptic number.

1400133000403 is a deficient number, since it is larger than the sum of its proper divisors (1028754485).

1400133000403 is a wasteful number, since it uses less digits than its factorization.

1400133000403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1028754484.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 1400133000403 its reverse (3040003310041), we get a palindrome (4440136310444).

The spelling of 1400133000403 in words is "one trillion, four hundred billion, one hundred thirty-three million, four hundred three", and thus it is an aban number.

Divisors: 1 1361 1028753123 1400133000403