Base | Representation |
---|---|
bin | 11111110101011101100011… |
… | …100111100111010011111011 |
3 | 200100202010211022202022222221 |
4 | 133311131203213213103323 |
5 | 121322434224403230243 |
6 | 1213441120551024511 |
7 | 41330425231152643 |
oct | 3765354347472373 |
9 | 610663738668887 |
10 | 140013310211323 |
11 | 40681347524a9a |
12 | 1385362636b137 |
13 | 6018277146ca3 |
14 | 2680974d27523 |
15 | 112c102cb7bed |
hex | 7f57639e74fb |
140013310211323 has 8 divisors (see below), whose sum is σ = 141719595194448. Its totient is φ = 138317335107744.
The previous prime is 140013310211297. The next prime is 140013310211347. The reversal of 140013310211323 is 323112013310041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 140013310211323 - 213 = 140013310203131 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140013310211023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2577442561 + ... + 2577496882.
It is an arithmetic number, because the mean of its divisors is an integer number (17714949399306).
Almost surely, 2140013310211323 is an apocalyptic number.
140013310211323 is a deficient number, since it is larger than the sum of its proper divisors (1706284983125).
140013310211323 is a wasteful number, since it uses less digits than its factorization.
140013310211323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5154939773.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 140013310211323 its reverse (323112013310041), we get a palindrome (463125323521364).
The spelling of 140013310211323 in words is "one hundred forty trillion, thirteen billion, three hundred ten million, two hundred eleven thousand, three hundred twenty-three".
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