Base | Representation |
---|---|
bin | 10100010111111110111… |
… | …010100011011001111001 |
3 | 11221212000020120010011001 |
4 | 110113332322203121321 |
5 | 140414442112232213 |
6 | 2551114351405001 |
7 | 203104542160540 |
oct | 24277672433171 |
9 | 4855006503131 |
10 | 1400141133433 |
11 | 49a884193999 |
12 | 1a7434523761 |
13 | a2056c20093 |
14 | 4baa5267157 |
15 | 2664a73c1dd |
hex | 145feea3679 |
1400141133433 has 4 divisors (see below), whose sum is σ = 1600161295360. Its totient is φ = 1200120971508.
The previous prime is 1400141133427. The next prime is 1400141133437. The reversal of 1400141133433 is 3343311410041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1400141133433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1400141133437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100010080953 + ... + 100010080966.
It is an arithmetic number, because the mean of its divisors is an integer number (400040323840).
Almost surely, 21400141133433 is an apocalyptic number.
It is an amenable number.
1400141133433 is a deficient number, since it is larger than the sum of its proper divisors (200020161927).
1400141133433 is an equidigital number, since it uses as much as digits as its factorization.
1400141133433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 200020161926.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1400141133433 its reverse (3343311410041), we get a palindrome (4743452543474).
The spelling of 1400141133433 in words is "one trillion, four hundred billion, one hundred forty-one million, one hundred thirty-three thousand, four hundred thirty-three".
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