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14001430214113 = 103419324430109
BaseRepresentation
bin1100101110111111011001…
…0001100011010111100001
31211120112010202010100200121
43023233312101203113201
53313344412113322423
645440100201320241
72643366331103026
oct313576621432741
954515122110617
1014001430214113
114508a78380721
1216a16a2796081
137a7438350ca4
1436595c3a754d
1519432176045d
hexcbbf64635e1

14001430214113 has 8 divisors (see below), whose sum is σ = 14171107204800. Its totient is φ = 13832402084688.

The previous prime is 14001430214077. The next prime is 14001430214141. The reversal of 14001430214113 is 31141203410041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14001430214113 - 225 = 14001396659681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14001430214183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 162171898 + ... + 162258211.

It is an arithmetic number, because the mean of its divisors is an integer number (1771388400600).

Almost surely, 214001430214113 is an apocalyptic number.

It is an amenable number.

14001430214113 is a deficient number, since it is larger than the sum of its proper divisors (169676990687).

14001430214113 is a wasteful number, since it uses less digits than its factorization.

14001430214113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 324430631.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14001430214113 its reverse (31141203410041), we get a palindrome (45142633624154).

The spelling of 14001430214113 in words is "fourteen trillion, one billion, four hundred thirty million, two hundred fourteen thousand, one hundred thirteen".

Divisors: 1 103 419 43157 324430109 33416301227 135936215671 14001430214113