14001441333441 has 4 divisors (see below), whose sum is σ = 18668588444592. Its totient is φ = 9334294222292.

The previous prime is 14001441333409. The next prime is 14001441333457. The reversal of 14001441333441 is 14433314410041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14001441333441 - 2⁵ = 14001441333409 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14001441333401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2333573555571 + ... + 2333573555576.

It is an arithmetic number, because the mean of its divisors is an integer number (4667147111148).

Almost surely, 2^{14001441333441} is an apocalyptic number.

It is an amenable number.

14001441333441 is a deficient number, since it is larger than the sum of its proper divisors (4667147111151).

14001441333441 is an equidigital number, since it uses as much as digits as its factorization.

14001441333441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4667147111150.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 14001441333441 its reverse (14433314410041), we get a palindrome (28434755743482).

The spelling of 14001441333441 in words is "fourteen trillion, one billion, four hundred forty-one million, three hundred thirty-three thousand, four hundred forty-one".