140020402022131 has 4 divisors (see below), whose sum is σ = 140020950116232. Its totient is φ = 140019853928032.

The previous prime is 140020402022113. The next prime is 140020402022143. The reversal of 140020402022131 is 131220204020041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140020402022131 - 2¹³ = 140020402013939 is a prime.

It is a super-2 number, since 2×140020402022131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140020402028131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 273663670 + ... + 274174843.

It is an arithmetic number, because the mean of its divisors is an integer number (35005237529058).

Almost surely, 2^{140020402022131} is an apocalyptic number.

140020402022131 is a deficient number, since it is larger than the sum of its proper divisors (548094101).

140020402022131 is an equidigital number, since it uses as much as digits as its factorization.

140020402022131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 548094100.

The product of its (nonzero) digits is 768, while the sum is 22.

Adding to 140020402022131 its reverse (131220204020041), we get a palindrome (271240606042172).

The spelling of 140020402022131 in words is "one hundred forty trillion, twenty billion, four hundred two million, twenty-two thousand, one hundred thirty-one".