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140022134001307 is a prime number
BaseRepresentation
bin11111110101100101110001…
…100011101100111010011011
3200100202222121021021022022101
4133311211301203230322123
5121323110312301020212
61213445140315304231
741331160004142115
oct3765456143547233
9610688537238271
10140022134001307
1140685065302008
121385528944b077
13601905224c4ac
142681170b903b5
15112c46c789157
hex7f59718ece9b

140022134001307 has 2 divisors, whose sum is σ = 140022134001308. Its totient is φ = 140022134001306.

The previous prime is 140022134001293. The next prime is 140022134001377. The reversal of 140022134001307 is 703100431220041.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140022134001307 is a prime.

It is a super-4 number, since 4×1400221340013074 (a number of 58 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (140022134001377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70011067000653 + 70011067000654.

It is an arithmetic number, because the mean of its divisors is an integer number (70011067000654).

Almost surely, 2140022134001307 is an apocalyptic number.

140022134001307 is a deficient number, since it is larger than the sum of its proper divisors (1).

140022134001307 is an equidigital number, since it uses as much as digits as its factorization.

140022134001307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 140022134001307 its reverse (703100431220041), we get a palindrome (843122565221348).

The spelling of 140022134001307 in words is "one hundred forty trillion, twenty-two billion, one hundred thirty-four million, one thousand, three hundred seven".