Base | Representation |
---|---|
bin | 1100101111000010011010… |
… | …1011000010011010011001 |
3 | 1211120121020100000120121221 |
4 | 3023300212223002122121 |
5 | 3313403043000414431 |
6 | 45440312525132041 |
7 | 2643425420633320 |
oct | 313604653023231 |
9 | 54517210016557 |
10 | 14002242201241 |
11 | 4509354759668 |
12 | 16a188a6ba021 |
13 | 7a7537640048 |
14 | 3659d81730b7 |
15 | 19436cba4111 |
hex | cbc26ac2699 |
14002242201241 has 4 divisors (see below), whose sum is σ = 16002562515712. Its totient is φ = 12001921886772.
The previous prime is 14002242201179. The next prime is 14002242201289. The reversal of 14002242201241 is 14210224220041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14002242201241 - 217 = 14002242070169 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14002242201041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1000160157225 + ... + 1000160157238.
It is an arithmetic number, because the mean of its divisors is an integer number (4000640628928).
Almost surely, 214002242201241 is an apocalyptic number.
It is an amenable number.
14002242201241 is a deficient number, since it is larger than the sum of its proper divisors (2000320314471).
14002242201241 is an equidigital number, since it uses as much as digits as its factorization.
14002242201241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2000320314470.
The product of its (nonzero) digits is 2048, while the sum is 25.
Adding to 14002242201241 its reverse (14210224220041), we get a palindrome (28212466421282).
The spelling of 14002242201241 in words is "fourteen trillion, two billion, two hundred forty-two million, two hundred one thousand, two hundred forty-one".
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