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140023100333353 is a prime number
BaseRepresentation
bin11111110101100110101011…
…001001111101110100101001
3200100210002002121121001200011
4133311212223021331310221
5121323114302141131403
61213445420235211521
741331222646626526
oct3765465311756451
9610702077531604
10140023100333353
114068551081a636
12138554b8ba6ba1
1360191774cbcc3
14268122325614d
15112c4c7519a6d
hex7f59ab27dd29

140023100333353 has 2 divisors, whose sum is σ = 140023100333354. Its totient is φ = 140023100333352.

The previous prime is 140023100333327. The next prime is 140023100333423. The reversal of 140023100333353 is 353333001320041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 135583364776729 + 4439735556624 = 11644027^2 + 2107068^2 .

It is a cyclic number.

It is not a de Polignac number, because 140023100333353 - 217 = 140023100202281 is a prime.

It is not a weakly prime, because it can be changed into another prime (140023100333453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70011550166676 + 70011550166677.

It is an arithmetic number, because the mean of its divisors is an integer number (70011550166677).

Almost surely, 2140023100333353 is an apocalyptic number.

It is an amenable number.

140023100333353 is a deficient number, since it is larger than the sum of its proper divisors (1).

140023100333353 is an equidigital number, since it uses as much as digits as its factorization.

140023100333353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 29160, while the sum is 31.

Adding to 140023100333353 its reverse (353333001320041), we get a palindrome (493356101653394).

The spelling of 140023100333353 in words is "one hundred forty trillion, twenty-three billion, one hundred million, three hundred thirty-three thousand, three hundred fifty-three".