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140023111209937 is a prime number
BaseRepresentation
bin11111110101100110101011…
…110011011101001111010001
3200100210002010101001122112121
4133311212223303131033101
5121323114312432204222
61213445421304254241
741331223141236634
oct3765465363351721
9610702111048477
10140023111209937
114068551697934a
1213855500771381
136019179839857
142681224887c1b
15112c4c84675c7
hex7f59abcdd3d1

140023111209937 has 2 divisors, whose sum is σ = 140023111209938. Its totient is φ = 140023111209936.

The previous prime is 140023111209859. The next prime is 140023111209967. The reversal of 140023111209937 is 739902111320041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138858861577921 + 1164249632016 = 11783839^2 + 1079004^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140023111209937 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140023111209893 and 140023111209902.

It is not a weakly prime, because it can be changed into another prime (140023111209967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70011555604968 + 70011555604969.

It is an arithmetic number, because the mean of its divisors is an integer number (70011555604969).

Almost surely, 2140023111209937 is an apocalyptic number.

It is an amenable number.

140023111209937 is a deficient number, since it is larger than the sum of its proper divisors (1).

140023111209937 is an equidigital number, since it uses as much as digits as its factorization.

140023111209937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 43.

Adding to 140023111209937 its reverse (739902111320041), we get a palindrome (879925222529978).

The spelling of 140023111209937 in words is "one hundred forty trillion, twenty-three billion, one hundred eleven million, two hundred nine thousand, nine hundred thirty-seven".