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140023401411302 = 2196143599841503
BaseRepresentation
bin11111110101100110111101…
…000110011111001011100110
3200100210002212121010101222022
4133311212331012133023212
5121323120411230130202
61213445510152303142
741331233264016023
oct3765467506371346
9610702777111868
10140023401411302
114068565576a992
12138555819a1ab2
1360191c49b6636
14268125122a54a
15112c4e3b8cea2
hex7f59bd19f2e6

140023401411302 has 16 divisors (see below), whose sum is σ = 221125572034560. Its totient is φ = 66316077095112.

The previous prime is 140023401411263. The next prime is 140023401411331. The reversal of 140023401411302 is 203114104320041.

It is a super-3 number, since 3×1400234014113023 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 299687318 + ... + 300154185.

It is an arithmetic number, because the mean of its divisors is an integer number (13820348252160).

Almost surely, 2140023401411302 is an apocalyptic number.

140023401411302 is a deficient number, since it is larger than the sum of its proper divisors (81102170623258).

140023401411302 is a wasteful number, since it uses less digits than its factorization.

140023401411302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 599847667.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 140023401411302 its reverse (203114104320041), we get a palindrome (343137505731343).

The spelling of 140023401411302 in words is "one hundred forty trillion, twenty-three billion, four hundred one million, four hundred eleven thousand, three hundred two".

Divisors: 1 2 19 38 6143 12286 116717 233434 599841503 1199683006 11396988557 22793977114 3684826352929 7369652705858 70011700705651 140023401411302