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140023442010043 is a prime number
BaseRepresentation
bin11111110101100110111111…
…100001010110111110111011
3200100210002222102112000222101
4133311212333201112332323
5121323121002123310133
61213445514202404231
741331234266056504
oct3765467741267673
9610702872460871
10140023442010043
114068567667a369
1213855593500677
13601920022c867
142681256797bab
15112c4e750c37d
hex7f59bf856fbb

140023442010043 has 2 divisors, whose sum is σ = 140023442010044. Its totient is φ = 140023442010042.

The previous prime is 140023442009963. The next prime is 140023442010047. The reversal of 140023442010043 is 340010244320041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140023442010043 is a prime.

It is a super-2 number, since 2×1400234420100432 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140023442009993 and 140023442010020.

It is not a weakly prime, because it can be changed into another prime (140023442010047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70011721005021 + 70011721005022.

It is an arithmetic number, because the mean of its divisors is an integer number (70011721005022).

Almost surely, 2140023442010043 is an apocalyptic number.

140023442010043 is a deficient number, since it is larger than the sum of its proper divisors (1).

140023442010043 is an equidigital number, since it uses as much as digits as its factorization.

140023442010043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 140023442010043 its reverse (340010244320041), we get a palindrome (480033686330084).

The spelling of 140023442010043 in words is "one hundred forty trillion, twenty-three billion, four hundred forty-two million, ten thousand, forty-three".