140030001244033 has 4 divisors (see below), whose sum is σ = 140030034264000. Its totient is φ = 140029968224068.

The previous prime is 140030001243901. The next prime is 140030001244039. The reversal of 140030001244033 is 330442100030041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140030001244033 - 2²⁹ = 140029464373121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140030001243989 and 140030001244007.

It is not an unprimeable number, because it can be changed into a prime (140030001244039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9014533 + ... + 19008466.

It is an arithmetic number, because the mean of its divisors is an integer number (35007508566000).

Almost surely, 2^{140030001244033} is an apocalyptic number.

It is an amenable number.

140030001244033 is a deficient number, since it is larger than the sum of its proper divisors (33019967).

140030001244033 is an equidigital number, since it uses as much as digits as its factorization.

140030001244033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33019966.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 140030001244033 its reverse (330442100030041), we get a palindrome (470472101274074).

The spelling of 140030001244033 in words is "one hundred forty trillion, thirty billion, one million, two hundred forty-four thousand, thirty-three".