Base | Representation |
---|---|
bin | 1100101111000101010010… |
… | …0001111000101011010001 |
3 | 1211120200012221200202012121 |
4 | 3023301110201320223101 |
5 | 3313411131424212001 |
6 | 45440521131054241 |
7 | 2643453452214301 |
oct | 313612441705321 |
9 | 54520187622177 |
10 | 14003011554001 |
11 | 4509709a67798 |
12 | 16a1a642a1381 |
13 | 7a762ab52472 |
14 | 365a6c401601 |
15 | 1943b54c56a1 |
hex | cbc54878ad1 |
14003011554001 has 2 divisors, whose sum is σ = 14003011554002. Its totient is φ = 14003011554000.
The previous prime is 14003011553917. The next prime is 14003011554031. The reversal of 14003011554001 is 10045511030041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7265477657025 + 6737533896976 = 2695455^2 + 2595676^2 .
It is a cyclic number.
It is not a de Polignac number, because 14003011554001 - 27 = 14003011553873 is a prime.
It is not a weakly prime, because it can be changed into another prime (14003011554031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001505777000 + 7001505777001.
It is an arithmetic number, because the mean of its divisors is an integer number (7001505777001).
Almost surely, 214003011554001 is an apocalyptic number.
It is an amenable number.
14003011554001 is a deficient number, since it is larger than the sum of its proper divisors (1).
14003011554001 is an equidigital number, since it uses as much as digits as its factorization.
14003011554001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 14003011554001 its reverse (10045511030041), we get a palindrome (24048522584042).
The spelling of 14003011554001 in words is "fourteen trillion, three billion, eleven million, five hundred fifty-four thousand, one".
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