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14003011554001 is a prime number
BaseRepresentation
bin1100101111000101010010…
…0001111000101011010001
31211120200012221200202012121
43023301110201320223101
53313411131424212001
645440521131054241
72643453452214301
oct313612441705321
954520187622177
1014003011554001
114509709a67798
1216a1a642a1381
137a762ab52472
14365a6c401601
151943b54c56a1
hexcbc54878ad1

14003011554001 has 2 divisors, whose sum is σ = 14003011554002. Its totient is φ = 14003011554000.

The previous prime is 14003011553917. The next prime is 14003011554031. The reversal of 14003011554001 is 10045511030041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7265477657025 + 6737533896976 = 2695455^2 + 2595676^2 .

It is a cyclic number.

It is not a de Polignac number, because 14003011554001 - 27 = 14003011553873 is a prime.

It is not a weakly prime, because it can be changed into another prime (14003011554031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001505777000 + 7001505777001.

It is an arithmetic number, because the mean of its divisors is an integer number (7001505777001).

Almost surely, 214003011554001 is an apocalyptic number.

It is an amenable number.

14003011554001 is a deficient number, since it is larger than the sum of its proper divisors (1).

14003011554001 is an equidigital number, since it uses as much as digits as its factorization.

14003011554001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 14003011554001 its reverse (10045511030041), we get a palindrome (24048522584042).

The spelling of 14003011554001 in words is "fourteen trillion, three billion, eleven million, five hundred fifty-four thousand, one".