14003113443131 has 2 divisors, whose sum is σ = 14003113443132. Its totient is φ = 14003113443130.

The previous prime is 14003113443083. The next prime is 14003113443157. The reversal of 14003113443131 is 13134431130041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14003113443131 - 2¹⁴ = 14003113426747 is a prime.

It is a super-3 number, since 3×14003113443131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14003113443094 and 14003113443103.

It is not a weakly prime, because it can be changed into another prime (14003113443161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001556721565 + 7001556721566.

It is an arithmetic number, because the mean of its divisors is an integer number (7001556721566).

Almost surely, 2^{14003113443131} is an apocalyptic number.

14003113443131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14003113443131 is an equidigital number, since it uses as much as digits as its factorization.

14003113443131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 14003113443131 its reverse (13134431130041), we get a palindrome (27137544573172).

The spelling of 14003113443131 in words is "fourteen trillion, three billion, one hundred thirteen million, four hundred forty-three thousand, one hundred thirty-one".