140032111134233 has 4 divisors (see below), whose sum is σ = 140033553330048. Its totient is φ = 140030668938420.

The previous prime is 140032111134197. The next prime is 140032111134241. The reversal of 140032111134233 is 332431111230041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140032111134233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140032111134196 and 140032111134205.

It is not an unprimeable number, because it can be changed into a prime (140032111134263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 720952253 + ... + 721146458.

It is an arithmetic number, because the mean of its divisors is an integer number (35008388332512).

Almost surely, 2^{140032111134233} is an apocalyptic number.

It is an amenable number.

140032111134233 is a deficient number, since it is larger than the sum of its proper divisors (1442195815).

140032111134233 is an equidigital number, since it uses as much as digits as its factorization.

140032111134233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1442195814.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 140032111134233 its reverse (332431111230041), we get a palindrome (472463222364274).

The spelling of 140032111134233 in words is "one hundred forty trillion, thirty-two billion, one hundred eleven million, one hundred thirty-four thousand, two hundred thirty-three".