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14003234313242 = 27001617156621
BaseRepresentation
bin1100101111000110000111…
…0011101001010000011010
31211120200210110212002102212
43023301201303221100122
53313412110441010432
645440555205355122
72643462125512166
oct313614163512032
954520713762385
1014003234313242
114509813785039
1216a1b06a08aa2
137a7665047a75
14365a8dc29ca6
151943c9d282b2
hexcbc61ce941a

14003234313242 has 4 divisors (see below), whose sum is σ = 21004851469866. Its totient is φ = 7001617156620.

The previous prime is 14003234313227. The next prime is 14003234313253. The reversal of 14003234313242 is 24231343230041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10967760921121 + 3035473392121 = 3311761^2 + 1742261^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14003234313199 and 14003234313208.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3500808578309 + ... + 3500808578312.

Almost surely, 214003234313242 is an apocalyptic number.

14003234313242 is a deficient number, since it is larger than the sum of its proper divisors (7001617156624).

14003234313242 is an equidigital number, since it uses as much as digits as its factorization.

14003234313242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7001617156623.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 14003234313242 its reverse (24231343230041), we get a palindrome (38234577543283).

The spelling of 14003234313242 in words is "fourteen trillion, three billion, two hundred thirty-four million, three hundred thirteen thousand, two hundred forty-two".

Divisors: 1 2 7001617156621 14003234313242