Base | Representation |
---|---|
bin | 1100101111000110000111… |
… | …0011101001010000011010 |
3 | 1211120200210110212002102212 |
4 | 3023301201303221100122 |
5 | 3313412110441010432 |
6 | 45440555205355122 |
7 | 2643462125512166 |
oct | 313614163512032 |
9 | 54520713762385 |
10 | 14003234313242 |
11 | 4509813785039 |
12 | 16a1b06a08aa2 |
13 | 7a7665047a75 |
14 | 365a8dc29ca6 |
15 | 1943c9d282b2 |
hex | cbc61ce941a |
14003234313242 has 4 divisors (see below), whose sum is σ = 21004851469866. Its totient is φ = 7001617156620.
The previous prime is 14003234313227. The next prime is 14003234313253. The reversal of 14003234313242 is 24231343230041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10967760921121 + 3035473392121 = 3311761^2 + 1742261^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14003234313199 and 14003234313208.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3500808578309 + ... + 3500808578312.
Almost surely, 214003234313242 is an apocalyptic number.
14003234313242 is a deficient number, since it is larger than the sum of its proper divisors (7001617156624).
14003234313242 is an equidigital number, since it uses as much as digits as its factorization.
14003234313242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7001617156623.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 14003234313242 its reverse (24231343230041), we get a palindrome (38234577543283).
The spelling of 14003234313242 in words is "fourteen trillion, three billion, two hundred thirty-four million, three hundred thirteen thousand, two hundred forty-two".
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