Base | Representation |
---|---|
bin | 11111110101110000000001… |
… | …101000111011001101110011 |
3 | 200100211001000101022011122022 |
4 | 133311300001220323031303 |
5 | 121323300333123134212 |
6 | 1213454200442302055 |
7 | 41332026532040222 |
oct | 3765600150731563 |
9 | 610731011264568 |
10 | 140033141224307 |
11 | 406897a3623621 |
12 | 1385743b7b792b |
13 | 601a0b78056b6 |
14 | 26818d69c0cb9 |
15 | 112c8b3ca3772 |
hex | 7f5c01a3b373 |
140033141224307 has 2 divisors, whose sum is σ = 140033141224308. Its totient is φ = 140033141224306.
The previous prime is 140033141224261. The next prime is 140033141224357. The reversal of 140033141224307 is 703422141330041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140033141224307 - 218 = 140033140962163 is a prime.
It is a super-2 number, since 2×1400331412243072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (140033141224357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70016570612153 + 70016570612154.
It is an arithmetic number, because the mean of its divisors is an integer number (70016570612154).
Almost surely, 2140033141224307 is an apocalyptic number.
140033141224307 is a deficient number, since it is larger than the sum of its proper divisors (1).
140033141224307 is an equidigital number, since it uses as much as digits as its factorization.
140033141224307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 140033141224307 its reverse (703422141330041), we get a palindrome (843455282554348).
The spelling of 140033141224307 in words is "one hundred forty trillion, thirty-three billion, one hundred forty-one million, two hundred twenty-four thousand, three hundred seven".
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