140033221103409 has 4 divisors (see below), whose sum is σ = 186710961471216. Its totient is φ = 93355480735604.

The previous prime is 140033221103357. The next prime is 140033221103441. The reversal of 140033221103409 is 904301122330041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140033221103409 is a prime.

It is a super-3 number, since 3×140033221103409³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 140033221103409.

It is not an unprimeable number, because it can be changed into a prime (140033221101409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23338870183899 + ... + 23338870183904.

It is an arithmetic number, because the mean of its divisors is an integer number (46677740367804).

Almost surely, 2^{140033221103409} is an apocalyptic number.

It is an amenable number.

140033221103409 is a deficient number, since it is larger than the sum of its proper divisors (46677740367807).

140033221103409 is an equidigital number, since it uses as much as digits as its factorization.

140033221103409 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46677740367806.

The product of its (nonzero) digits is 15552, while the sum is 33.

The spelling of 140033221103409 in words is "one hundred forty trillion, thirty-three billion, two hundred twenty-one million, one hundred three thousand, four hundred nine".