Base | Representation |
---|---|
bin | 11111110101110000010011… |
… | …101001101101110010001011 |
3 | 200100211001210102221101000101 |
4 | 133311300103221231302023 |
5 | 121323301443003440243 |
6 | 1213454250435350231 |
7 | 41332040161500124 |
oct | 3765602351556213 |
9 | 610731712841011 |
10 | 140033443421323 |
11 | 40689939168721 |
12 | 13857504a52377 |
13 | 601a1352c24ba |
14 | 2681924ba704b |
15 | 112c8d059854d |
hex | 7f5c13a6dc8b |
140033443421323 has 4 divisors (see below), whose sum is σ = 140054819316048. Its totient is φ = 140012067526600.
The previous prime is 140033443421293. The next prime is 140033443421329. The reversal of 140033443421323 is 323124344330041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140033443421323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (140033443421329) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10687937536 + ... + 10687950637.
It is an arithmetic number, because the mean of its divisors is an integer number (35013704829012).
Almost surely, 2140033443421323 is an apocalyptic number.
140033443421323 is a deficient number, since it is larger than the sum of its proper divisors (21375894725).
140033443421323 is an equidigital number, since it uses as much as digits as its factorization.
140033443421323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21375894724.
The product of its (nonzero) digits is 248832, while the sum is 37.
Adding to 140033443421323 its reverse (323124344330041), we get a palindrome (463157787751364).
The spelling of 140033443421323 in words is "one hundred forty trillion, thirty-three billion, four hundred forty-three million, four hundred twenty-one thousand, three hundred twenty-three".
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