Base | Representation |
---|---|
bin | 1000001001101010100… |
… | …1100111101010101010 |
3 | 111101110011211122201012 |
4 | 2002122221213222222 |
5 | 4243242042230424 |
6 | 144155221023522 |
7 | 13055106402425 |
oct | 2023251475252 |
9 | 441404748635 |
10 | 140033555114 |
11 | 5442a322642 |
12 | 23180b54ba2 |
13 | 102888101ab |
14 | 6ac5c849bc |
15 | 3998b4db0e |
hex | 209aa67aaa |
140033555114 has 4 divisors (see below), whose sum is σ = 210050332674. Its totient is φ = 70016777556.
The previous prime is 140033555041. The next prime is 140033555119. The reversal of 140033555114 is 411555330041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 104532589225 + 35500965889 = 323315^2 + 188417^2 .
It is not an unprimeable number, because it can be changed into a prime (140033555119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35008388777 + ... + 35008388780.
Almost surely, 2140033555114 is an apocalyptic number.
140033555114 is a deficient number, since it is larger than the sum of its proper divisors (70016777560).
140033555114 is an equidigital number, since it uses as much as digits as its factorization.
140033555114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70016777559.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 140033555114 its reverse (411555330041), we get a palindrome (551588885155).
The spelling of 140033555114 in words is "one hundred forty billion, thirty-three million, five hundred fifty-five thousand, one hundred fourteen".
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