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140034315413042 = 2139950048004079
BaseRepresentation
bin11111110101110001000111…
…101000000110011000110010
3200100211011001012202010202222
4133311301013220012120302
5121323310234221204132
61213454513145241042
741332100610344051
oct3765610750063062
9610734035663688
10140034315413042
114068a2463aaa36
1213857708a93182
13601a243b6062b
1426819a8912398
15112c931de1412
hex7f5c47a06632

140034315413042 has 8 divisors (see below), whose sum is σ = 210201617136000. Its totient is φ = 69967109701044.

The previous prime is 140034315413033. The next prime is 140034315413059. The reversal of 140034315413042 is 240314513430041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 140034315412993 and 140034315413011.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25023999242 + ... + 25024004837.

It is an arithmetic number, because the mean of its divisors is an integer number (26275202142000).

Almost surely, 2140034315413042 is an apocalyptic number.

140034315413042 is a deficient number, since it is larger than the sum of its proper divisors (70167301722958).

140034315413042 is a wasteful number, since it uses less digits than its factorization.

140034315413042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50048005480.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 140034315413042 its reverse (240314513430041), we get a palindrome (380348828843083).

The spelling of 140034315413042 in words is "one hundred forty trillion, thirty-four billion, three hundred fifteen million, four hundred thirteen thousand, forty-two".

Divisors: 1 2 1399 2798 50048004079 100096008158 70017157706521 140034315413042