Base | Representation |
---|---|
bin | 11111110101110001000111… |
… | …101000000110011000110010 |
3 | 200100211011001012202010202222 |
4 | 133311301013220012120302 |
5 | 121323310234221204132 |
6 | 1213454513145241042 |
7 | 41332100610344051 |
oct | 3765610750063062 |
9 | 610734035663688 |
10 | 140034315413042 |
11 | 4068a2463aaa36 |
12 | 13857708a93182 |
13 | 601a243b6062b |
14 | 26819a8912398 |
15 | 112c931de1412 |
hex | 7f5c47a06632 |
140034315413042 has 8 divisors (see below), whose sum is σ = 210201617136000. Its totient is φ = 69967109701044.
The previous prime is 140034315413033. The next prime is 140034315413059. The reversal of 140034315413042 is 240314513430041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 140034315412993 and 140034315413011.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25023999242 + ... + 25024004837.
It is an arithmetic number, because the mean of its divisors is an integer number (26275202142000).
Almost surely, 2140034315413042 is an apocalyptic number.
140034315413042 is a deficient number, since it is larger than the sum of its proper divisors (70167301722958).
140034315413042 is a wasteful number, since it uses less digits than its factorization.
140034315413042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50048005480.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 140034315413042 its reverse (240314513430041), we get a palindrome (380348828843083).
The spelling of 140034315413042 in words is "one hundred forty trillion, thirty-four billion, three hundred fifteen million, four hundred thirteen thousand, forty-two".
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