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140034320240147 is a prime number
BaseRepresentation
bin11111110101110001000111…
…111010100000111000010011
3200100211011001112211101022122
4133311301013322200320103
5121323310241440141042
61213454513440524455
741332100666360204
oct3765610772407023
9610734045741278
10140034320240147
114068a2490a7683
121385770a62072b
13601a244b607c8
1426819a940b5ab
15112c9325467d2
hex7f5c47ea0e13

140034320240147 has 2 divisors, whose sum is σ = 140034320240148. Its totient is φ = 140034320240146.

The previous prime is 140034320240131. The next prime is 140034320240189. The reversal of 140034320240147 is 741042023430041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 140034320240147 - 24 = 140034320240131 is a prime.

It is a super-3 number, since 3×1400343202401473 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (140034320245147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70017160120073 + 70017160120074.

It is an arithmetic number, because the mean of its divisors is an integer number (70017160120074).

Almost surely, 2140034320240147 is an apocalyptic number.

140034320240147 is a deficient number, since it is larger than the sum of its proper divisors (1).

140034320240147 is an equidigital number, since it uses as much as digits as its factorization.

140034320240147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 35.

Adding to 140034320240147 its reverse (741042023430041), we get a palindrome (881076343670188).

The spelling of 140034320240147 in words is "one hundred forty trillion, thirty-four billion, three hundred twenty million, two hundred forty thousand, one hundred forty-seven".