Base | Representation |
---|---|
bin | 11111110101110001000111… |
… | …111010100000111000010011 |
3 | 200100211011001112211101022122 |
4 | 133311301013322200320103 |
5 | 121323310241440141042 |
6 | 1213454513440524455 |
7 | 41332100666360204 |
oct | 3765610772407023 |
9 | 610734045741278 |
10 | 140034320240147 |
11 | 4068a2490a7683 |
12 | 1385770a62072b |
13 | 601a244b607c8 |
14 | 26819a940b5ab |
15 | 112c9325467d2 |
hex | 7f5c47ea0e13 |
140034320240147 has 2 divisors, whose sum is σ = 140034320240148. Its totient is φ = 140034320240146.
The previous prime is 140034320240131. The next prime is 140034320240189. The reversal of 140034320240147 is 741042023430041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140034320240147 - 24 = 140034320240131 is a prime.
It is a super-3 number, since 3×1400343202401473 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (140034320245147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70017160120073 + 70017160120074.
It is an arithmetic number, because the mean of its divisors is an integer number (70017160120074).
Almost surely, 2140034320240147 is an apocalyptic number.
140034320240147 is a deficient number, since it is larger than the sum of its proper divisors (1).
140034320240147 is an equidigital number, since it uses as much as digits as its factorization.
140034320240147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 140034320240147 its reverse (741042023430041), we get a palindrome (881076343670188).
The spelling of 140034320240147 in words is "one hundred forty trillion, thirty-four billion, three hundred twenty million, two hundred forty thousand, one hundred forty-seven".
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