1400411124313 has 4 divisors (see below), whose sum is σ = 1400446475280. Its totient is φ = 1400375773348.

The previous prime is 1400411124289. The next prime is 1400411124341. The reversal of 1400411124313 is 3134211140041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1400411124313 is a prime.

It is a super-2 number, since 2×1400411124313² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1400411124113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17615995 + ... + 17695312.

It is an arithmetic number, because the mean of its divisors is an integer number (350111618820).

Almost surely, 2^{1400411124313} is an apocalyptic number.

It is an amenable number.

1400411124313 is a deficient number, since it is larger than the sum of its proper divisors (35350967).

1400411124313 is an equidigital number, since it uses as much as digits as its factorization.

1400411124313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35350966.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1400411124313 its reverse (3134211140041), we get a palindrome (4534622264354).

The spelling of 1400411124313 in words is "one trillion, four hundred billion, four hundred eleven million, one hundred twenty-four thousand, three hundred thirteen".