Base | Representation |
---|---|
bin | 10100011000001111001… |
… | …001001101101011001011 |
3 | 11221212201012220022012000 |
4 | 110120033021031223023 |
5 | 140421021313141133 |
6 | 2551201355322043 |
7 | 203114356411662 |
oct | 24301711155313 |
9 | 4855635808160 |
10 | 1400413412043 |
11 | 49aa03953938 |
12 | 1a74ab750323 |
13 | a209b463099 |
14 | 4bacd4a1dd9 |
15 | 266645c2413 |
hex | 1460f24dacb |
1400413412043 has 8 divisors (see below), whose sum is σ = 2074686536400. Its totient is φ = 933608941344.
The previous prime is 1400413412033. The next prime is 1400413412093. The reversal of 1400413412043 is 3402143140041.
1400413412043 is a `hidden beast` number, since 1 + 4 + 0 + 0 + 413 + 41 + 204 + 3 = 666.
It is not a de Polignac number, because 1400413412043 - 25 = 1400413412011 is a prime.
It is a super-2 number, since 2×14004134120432 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 51867163409 = 1400413412043 / (1 + 4 + 0 + 0 + 4 + 1 + 3 + 4 + 1 + 2 + 0 + 4 + 3).
It is a junction number, because it is equal to n+sod(n) for n = 1400413411998 and 1400413412016.
It is not an unprimeable number, because it can be changed into a prime (1400413412033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25933581678 + ... + 25933581731.
It is an arithmetic number, because the mean of its divisors is an integer number (259335817050).
Almost surely, 21400413412043 is an apocalyptic number.
1400413412043 is a deficient number, since it is larger than the sum of its proper divisors (674273124357).
1400413412043 is an equidigital number, since it uses as much as digits as its factorization.
1400413412043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51867163418 (or 51867163412 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 1400413412043 its reverse (3402143140041), we get a palindrome (4802556552084).
The spelling of 1400413412043 in words is "one trillion, four hundred billion, four hundred thirteen million, four hundred twelve thousand, forty-three".
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