140043312121 has 4 divisors (see below), whose sum is σ = 141402956032. Its totient is φ = 138683668212.

The previous prime is 140043312089. The next prime is 140043312131. The reversal of 140043312121 is 121213340041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140043312121 - 2⁵ = 140043312089 is a prime.

It is a super-2 number, since 2×140043312121² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140043312092 and 140043312101.

It is not an unprimeable number, because it can be changed into a prime (140043312131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 679821801 + ... + 679822006.

It is an arithmetic number, because the mean of its divisors is an integer number (35350739008).

Almost surely, 2^140043312121 is an apocalyptic number.

It is an amenable number.

140043312121 is a deficient number, since it is larger than the sum of its proper divisors (1359643911).

140043312121 is a wasteful number, since it uses less digits than its factorization.

140043312121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1359643910.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 140043312121 its reverse (121213340041), we get a palindrome (261256652162).

The spelling of 140043312121 in words is "one hundred forty billion, forty-three million, three hundred twelve thousand, one hundred twenty-one".