140043323411041 has 2 divisors, whose sum is σ = 140043323411042. Its totient is φ = 140043323411040.

The previous prime is 140043323411011. The next prime is 140043323411053. The reversal of 140043323411041 is 140114323340041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99522651018816 + 40520672392225 = 9976104^2 + 6365585^2 .

It is a cyclic number.

It is not a de Polignac number, because 140043323411041 - 2¹³ = 140043323402849 is a prime.

It is a super-2 number, since 2×140043323411041² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140043323410994 and 140043323411012.

It is not a weakly prime, because it can be changed into another prime (140043323411011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70021661705520 + 70021661705521.

It is an arithmetic number, because the mean of its divisors is an integer number (70021661705521).

Almost surely, 2^{140043323411041} is an apocalyptic number.

It is an amenable number.

140043323411041 is a deficient number, since it is larger than the sum of its proper divisors (1).

140043323411041 is an equidigital number, since it uses as much as digits as its factorization.

140043323411041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 140043323411041 its reverse (140114323340041), we get a palindrome (280157646751082).

The spelling of 140043323411041 in words is "one hundred forty trillion, forty-three billion, three hundred twenty-three million, four hundred eleven thousand, forty-one".