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1400434401203 is a prime number
BaseRepresentation
bin10100011000010000011…
…001010001111110110011
311221212202200101122220022
4110120100121101332303
5140421042201314303
62551203425234055
7203115033000605
oct24302031217663
94855680348808
101400434401203
1149aa1478a352
121a74b679292b
13a20a29017c6
144bad21a7175
152666636b438
hex14610651fb3

1400434401203 has 2 divisors, whose sum is σ = 1400434401204. Its totient is φ = 1400434401202.

The previous prime is 1400434401181. The next prime is 1400434401299. The reversal of 1400434401203 is 3021044340041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1400434401203 - 218 = 1400434139059 is a prime.

It is a super-2 number, since 2×14004344012032 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1400434401403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700217200601 + 700217200602.

It is an arithmetic number, because the mean of its divisors is an integer number (700217200602).

Almost surely, 21400434401203 is an apocalyptic number.

1400434401203 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400434401203 is an equidigital number, since it uses as much as digits as its factorization.

1400434401203 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 1400434401203 its reverse (3021044340041), we get a palindrome (4421478741244).

The spelling of 1400434401203 in words is "one trillion, four hundred billion, four hundred thirty-four million, four hundred one thousand, two hundred three".