Base | Representation |
---|---|
bin | 11010000101011101… |
… | …01100110011110001 |
3 | 1100010222211021112021 |
4 | 31002232230303301 |
5 | 212140114042210 |
6 | 10233351431441 |
7 | 1004020531012 |
oct | 150256546361 |
9 | 40128737467 |
10 | 14004440305 |
11 | 5a37161309 |
12 | 286a085581 |
13 | 1422504c8b |
14 | 96bd11009 |
15 | 56e70dbda |
hex | 342baccf1 |
14004440305 has 32 divisors (see below), whose sum is σ = 17540167680. Its totient is φ = 10726000320.
The previous prime is 14004440293. The next prime is 14004440311. The reversal of 14004440305 is 50304440041.
It is not a de Polignac number, because 14004440305 - 25 = 14004440273 is a prime.
It is a super-2 number, since 2×140044403052 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14004440305.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2923122 + ... + 2927908.
It is an arithmetic number, because the mean of its divisors is an integer number (548130240).
Almost surely, 214004440305 is an apocalyptic number.
It is an amenable number.
14004440305 is a deficient number, since it is larger than the sum of its proper divisors (3535727375).
14004440305 is a wasteful number, since it uses less digits than its factorization.
14004440305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5109.
The product of its (nonzero) digits is 3840, while the sum is 25.
Adding to 14004440305 its reverse (50304440041), we get a palindrome (64308880346).
The spelling of 14004440305 in words is "fourteen billion, four million, four hundred forty thousand, three hundred five".
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