14004441331 has 2 divisors, whose sum is σ = 14004441332. Its totient is φ = 14004441330.

The previous prime is 14004441313. The next prime is 14004441361. The reversal of 14004441331 is 13314440041.

Together with previous prime (14004441313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14004441331 - 2¹³ = 14004433139 is a prime.

It is a super-2 number, since 2×14004441331² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14004441296 and 14004441305.

It is not a weakly prime, because it can be changed into another prime (14004441361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002220665 + 7002220666.

It is an arithmetic number, because the mean of its divisors is an integer number (7002220666).

Almost surely, 2^14004441331 is an apocalyptic number.

14004441331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14004441331 is an equidigital number, since it uses as much as digits as its factorization.

14004441331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14004441331 its reverse (13314440041), we get a palindrome (27318881372).

The spelling of 14004441331 in words is "fourteen billion, four million, four hundred forty-one thousand, three hundred thirty-one".