Base | Representation |
---|---|
bin | 11010000101011101… |
… | …01110000100000011 |
3 | 1100010222211112120120 |
4 | 31002232232010003 |
5 | 212140114223233 |
6 | 10233351511323 |
7 | 1004020552002 |
oct | 150256560403 |
9 | 40128745516 |
10 | 14004445443 |
11 | 5a3716515a |
12 | 286a088543 |
13 | 1422507411 |
14 | 96bd12c39 |
15 | 56e7104b3 |
hex | 342bae103 |
14004445443 has 4 divisors (see below), whose sum is σ = 18672593928. Its totient is φ = 9336296960.
The previous prime is 14004445423. The next prime is 14004445447. The reversal of 14004445443 is 34454440041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14004445443 - 214 = 14004429059 is a prime.
It is a super-2 number, since 2×140044454432 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14004445447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2334074238 + ... + 2334074243.
It is an arithmetic number, because the mean of its divisors is an integer number (4668148482).
Almost surely, 214004445443 is an apocalyptic number.
14004445443 is a deficient number, since it is larger than the sum of its proper divisors (4668148485).
14004445443 is an equidigital number, since it uses as much as digits as its factorization.
14004445443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4668148484.
The product of its (nonzero) digits is 61440, while the sum is 33.
Adding to 14004445443 its reverse (34454440041), we get a palindrome (48458885484).
The spelling of 14004445443 in words is "fourteen billion, four million, four hundred forty-five thousand, four hundred forty-three".
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