Base | Representation |
---|---|
bin | 1000001001101110100… |
… | …0100001010110011001 |
3 | 111101111022212101122021 |
4 | 2002123220201112121 |
5 | 4243310302404223 |
6 | 144201010254441 |
7 | 13055366510044 |
oct | 2023350412631 |
9 | 441438771567 |
10 | 140050044313 |
11 | 54438665183 |
12 | 23186587421 |
13 | 1028c06460a |
14 | 6ac8137c5b |
15 | 399a30965d |
hex | 209ba21599 |
140050044313 has 2 divisors, whose sum is σ = 140050044314. Its totient is φ = 140050044312.
The previous prime is 140050044271. The next prime is 140050044347. The reversal of 140050044313 is 313440050041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 136868181849 + 3181862464 = 369957^2 + 56408^2 .
It is a cyclic number.
It is not a de Polignac number, because 140050044313 - 29 = 140050043801 is a prime.
It is a super-2 number, since 2×1400500443132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (140050044353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70025022156 + 70025022157.
It is an arithmetic number, because the mean of its divisors is an integer number (70025022157).
Almost surely, 2140050044313 is an apocalyptic number.
It is an amenable number.
140050044313 is a deficient number, since it is larger than the sum of its proper divisors (1).
140050044313 is an equidigital number, since it uses as much as digits as its factorization.
140050044313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 140050044313 its reverse (313440050041), we get a palindrome (453490094354).
The spelling of 140050044313 in words is "one hundred forty billion, fifty million, forty-four thousand, three hundred thirteen".
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