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14005113121 = 56324875867
BaseRepresentation
bin11010000101100010…
…10001000100100001
31100011001002110110101
431002301101010201
5212140302104441
610233414102401
71004026332406
oct150261210441
940131073411
1014005113121
115a3758085a
12286a34aa01
1314226ac2ac
1496c0482ad
1556e7e3231
hex342c51121

14005113121 has 4 divisors (see below), whose sum is σ = 14029989552. Its totient is φ = 13980236692.

The previous prime is 14005113119. The next prime is 14005113139. The reversal of 14005113121 is 12131150041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14005113121 - 21 = 14005113119 is a prime.

It is a super-2 number, since 2×140051131212 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14005113821) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12437371 + ... + 12438496.

It is an arithmetic number, because the mean of its divisors is an integer number (3507497388).

Almost surely, 214005113121 is an apocalyptic number.

It is an amenable number.

14005113121 is a deficient number, since it is larger than the sum of its proper divisors (24876431).

14005113121 is an equidigital number, since it uses as much as digits as its factorization.

14005113121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24876430.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 14005113121 its reverse (12131150041), we get a palindrome (26136263162).

The spelling of 14005113121 in words is "fourteen billion, five million, one hundred thirteen thousand, one hundred twenty-one".

Divisors: 1 563 24875867 14005113121