Base | Representation |
---|---|
bin | 10100011000010110010… |
… | …001110101100100110011 |
3 | 11221220000120010202012221 |
4 | 110120112101311210303 |
5 | 140421242434110024 |
6 | 2551221313101511 |
7 | 203120342016526 |
oct | 24302621654463 |
9 | 4856016122187 |
10 | 1400533113139 |
11 | 49aa65481066 |
12 | 1a7523857897 |
13 | a20ba1b3c34 |
14 | 4bb01340bbd |
15 | 2666ed693e4 |
hex | 14616475933 |
1400533113139 has 2 divisors, whose sum is σ = 1400533113140. Its totient is φ = 1400533113138.
The previous prime is 1400533113131. The next prime is 1400533113157. The reversal of 1400533113139 is 9313113350041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1400533113139 - 23 = 1400533113131 is a prime.
It is a super-2 number, since 2×14005331131392 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1400533113131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700266556569 + 700266556570.
It is an arithmetic number, because the mean of its divisors is an integer number (700266556570).
Almost surely, 21400533113139 is an apocalyptic number.
1400533113139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400533113139 is an equidigital number, since it uses as much as digits as its factorization.
1400533113139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 34.
The spelling of 1400533113139 in words is "one trillion, four hundred billion, five hundred thirty-three million, one hundred thirteen thousand, one hundred thirty-nine".
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