Base | Representation |
---|---|
bin | 1100101111010000111000… |
… | …0100001100000011001011 |
3 | 1211120222020212221012210102 |
4 | 3023310032010030003023 |
5 | 3313434020312044321 |
6 | 45442154044440015 |
7 | 2643623550326435 |
oct | 313641604140313 |
9 | 54528225835712 |
10 | 14006124331211 |
11 | 450aa67056341 |
12 | 16a259284900b |
13 | 7a7a05a0217c |
14 | 365c859a3655 |
15 | 1944e88e4c0b |
hex | cbd0e10c0cb |
14006124331211 has 2 divisors, whose sum is σ = 14006124331212. Its totient is φ = 14006124331210.
The previous prime is 14006124331201. The next prime is 14006124331219. The reversal of 14006124331211 is 11213342160041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14006124331211 - 214 = 14006124314827 is a prime.
It is not a weakly prime, because it can be changed into another prime (14006124331219) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7003062165605 + 7003062165606.
It is an arithmetic number, because the mean of its divisors is an integer number (7003062165606).
Almost surely, 214006124331211 is an apocalyptic number.
14006124331211 is a deficient number, since it is larger than the sum of its proper divisors (1).
14006124331211 is an equidigital number, since it uses as much as digits as its factorization.
14006124331211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 14006124331211 its reverse (11213342160041), we get a palindrome (25219466491252).
The spelling of 14006124331211 in words is "fourteen trillion, six billion, one hundred twenty-four million, three hundred thirty-one thousand, two hundred eleven".
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