Base | Representation |
---|---|
bin | 1100101111010001101011… |
… | …1111111110101001011010 |
3 | 1211120222211000020222021212 |
4 | 3023310122333332221122 |
5 | 3313434441340102141 |
6 | 45442231355503122 |
7 | 2643632123650454 |
oct | 313643277765132 |
9 | 54528730228255 |
10 | 14006341331546 |
11 | 451006859a963 |
12 | 16a2633457aa2 |
13 | 7a7a3b95c435 |
14 | 365ca672d2d4 |
15 | 19450c9ab2eb |
hex | cbd1affea5a |
14006341331546 has 4 divisors (see below), whose sum is σ = 21009511997322. Its totient is φ = 7003170665772.
The previous prime is 14006341331509. The next prime is 14006341331557. The reversal of 14006341331546 is 64513314360041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 7254861445225 + 6751479886321 = 2693485^2 + 2598361^2 .
It is a super-3 number, since 3×140063413315463 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3501585332885 + ... + 3501585332888.
Almost surely, 214006341331546 is an apocalyptic number.
14006341331546 is a deficient number, since it is larger than the sum of its proper divisors (7003170665776).
14006341331546 is an equidigital number, since it uses as much as digits as its factorization.
14006341331546 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7003170665775.
The product of its (nonzero) digits is 311040, while the sum is 41.
Adding to 14006341331546 its reverse (64513314360041), we get a palindrome (78519655691587).
The spelling of 14006341331546 in words is "fourteen trillion, six billion, three hundred forty-one million, three hundred thirty-one thousand, five hundred forty-six".
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