140100433201331 has 4 divisors (see below), whose sum is σ = 140137684051464. Its totient is φ = 140063182351200.

The previous prime is 140100433201327. The next prime is 140100433201367. The reversal of 140100433201331 is 133102334001041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140100433201331 - 2² = 140100433201327 is a prime.

It is a super-2 number, since 2×140100433201331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140100433201331.

It is not an unprimeable number, because it can be changed into a prime (140100433231331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18625419425 + ... + 18625426946.

It is an arithmetic number, because the mean of its divisors is an integer number (35034421012866).

Almost surely, 2^{140100433201331} is an apocalyptic number.

140100433201331 is a deficient number, since it is larger than the sum of its proper divisors (37250850133).

140100433201331 is an equidigital number, since it uses as much as digits as its factorization.

140100433201331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37250850132.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 140100433201331 its reverse (133102334001041), we get a palindrome (273202767202372).

The spelling of 140100433201331 in words is "one hundred forty trillion, one hundred billion, four hundred thirty-three million, two hundred one thousand, three hundred thirty-one".