1401004353233 has 2 divisors, whose sum is σ = 1401004353234. Its totient is φ = 1401004353232.

The previous prime is 1401004353193. The next prime is 1401004353247. The reversal of 1401004353233 is 3323534001041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1319851727104 + 81152626129 = 1148848^2 + 284873^2 .

It is an emirp because it is prime and its reverse (3323534001041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1401004353233 - 2³² = 1396709385937 is a prime.

It is a super-3 number, since 3×1401004353233³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1401004353196 and 1401004353205.

It is not a weakly prime, because it can be changed into another prime (1401004359233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700502176616 + 700502176617.

It is an arithmetic number, because the mean of its divisors is an integer number (700502176617).

Almost surely, 2^{1401004353233} is an apocalyptic number.

It is an amenable number.

1401004353233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401004353233 is an equidigital number, since it uses as much as digits as its factorization.

1401004353233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 1401004353233 its reverse (3323534001041), we get a palindrome (4724538354274).

The spelling of 1401004353233 in words is "one trillion, four hundred one billion, four million, three hundred fifty-three thousand, two hundred thirty-three".